find molarity of Alcl3 if it normality is 0.2N.
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Answer:
Normality = Molarity × n factorn
factor of a salt = Its total positive or negative charge.
In AlCl3, Al has +3 chargeand Cl has −1 charge = −3.
Thus n=3Normality = Molarity × n factor0.2 = M × 3Molarity=0.23
=0.0667 M
Explanation:
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Answered by
3
Answer:
0.0667M
Explanation:
molarity= 0.0667 M
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