find molarity of solution containing 30gm of KOH is 500ml of water
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Answer:
M = molar concentration
n = moles of solute
v = liters of solution
Potassium Hydroxide (KOH) 56.105 11.7
0.017823520059659 mole = 1 gram of (KOH)
0.5347056017897 mole = 30 gram of (KOH)
molarity = number of moles / litres of water
0.5347056017897/0.5
0.534705602/0.5
1.087411204
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