Question

Find mole-fraction of each component in 180 gm ethanol and 108gm water.​

Answer 1

Answer:

HOPE IT HELPS...PLS COMMENT IF WRONG..THNX

Answer 2

Concept:

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Given:

The mass of ethanol = 180 g

The mass of water = 108 g

Find:

Find the mole fraction of each component in 180 g ethanol and 108 g water.​

Solution:

The number of moles (n) of a component can be calculated as:

                       n = Mass / Molar mass

Molar mass of ethanol = 46g/mol

The molar mass of water = 18 g/mol

The number of moles of ethanol = 180 g / 46 g/mol = 3.9 mol = 4 moles

The number of moles of water = 108 g / 18 g/mol = 6 moles

The mole fraction of ethanol can be calculated as follows below.

Mole fraction of ethanol =  Number of moles of ethanol / ( Number of moles of ethanol + Number of moles of water)

= 4 moles / (4 + 6) moles

= 4 / 10

= 0.4

Mole fraction of water = Number of moles of water / ( number of moles of ethanol + number of moles of water)

= 6 moles / (4 + 6) moles

= 6 / 10

= 0.6

Hence, the mole fraction of each component in 180 g ethanol and 108 g water are 0.4 and 0.6 respectively.

#SPJ2