Question

find mole of 111g of Cacl2. a) find no. of Ca. b) find no. of cl. c) find no. of Cacl2​

Answer 1

Explanation:

Gram molecular weight of CaCl2= 40 + 35.5 + 35.5 =111g

A)

111 g of CaCl2 = 1 mole of CaCl2

1 mole of CaCl2 = 6.023 × 10²³ molecules

B)

1 molecule of CaCl2 has 1 molecule ofCa

1 mole of CaCl2 =1 mole of Ca

Therefore number of Ca atoms = 6.023×10²³

C)

1 molecule of CaCl2 = 2 molecules of Cl

6.023× 10²³ molecules = ? molecules of Cl

=2×6.023×10²³ atoms of Cl

=12.046 × 10²³ atoms of Cl