Question

find mole of electron in 64 g of CH4

Answer 1

24* 10 raised to 23 moleculesI mole of methane contains Na ( avogadro number- 6.023 * 10raised to 23 molecules) The molecular mass of 1 mole of methane is C + 4*H= 12+ 4*1= 16 g16*4= 64. So, If 1 mole of methane has 16g4 moles of methane have 64g.Also, 1 mole has 6*10 raised to 23 molecules. So 4 moles have 4*6*10 raised to 23 molecules = 24* 10 raised to 23 molecules