find moment of inertia of disc by using proper integration.
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cut an element dx at x distance from centre ,
mass of element(dm )={m/πR²/2).πxdx
= 2m/R²x.dx
moment of inertia (dI) = dm.x²
dI = 2m/R²x³dx
integrated
I = 2m/R²/4 [ x⁴]
you didn't mention which axis ,
about Centre
I = mR²/2
about centre of mass ,
use perpendicular axis theorem ,
I = Ix + Iy
I = 2Ix
Ix = mR²/4
so, moment of inertia = mR²/4
mass of element(dm )={m/πR²/2).πxdx
= 2m/R²x.dx
moment of inertia (dI) = dm.x²
dI = 2m/R²x³dx
integrated
I = 2m/R²/4 [ x⁴]
you didn't mention which axis ,
about Centre
I = mR²/2
about centre of mass ,
use perpendicular axis theorem ,
I = Ix + Iy
I = 2Ix
Ix = mR²/4
so, moment of inertia = mR²/4
abhi178:
i am not sure may be wrong
wrong dear abhi!!!
sorry i forgot some concept , so this will be wrong
now this is correct
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see attachment....hope it will help u
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