Question

find n,4^n+4^n+4^n+4^n=2^2010​

Answer 1

$4^n+4^n+4^n+4^n=2^{2010}\\4\cdot4^n=2^{2010}\\4^{n+1}=2^{2010}\\2^{2(n+1)}=2^{2010}\\2(n+1)=2010\\2n+2=2010\\2n=2008\\n=1004$