Question

Find N: (8/3)^2n+1*(8/3)^5=(8/3)^n+2

Answer 1

Solution :

$( { \frac{8}{3}) }^{2n + 1} \times { (\frac{8}{3}) }^{5} = { \frac{8}{3} }^{n + 2}$

$\implies \: \: 2n + 1 + 5 = n + 2 \\ \implies \: 2n + 6 = n + 2$

$\implies \: 2n - n = 2- 6 \\ \implies \: n = - 4$

$\tt \: { \red{n = - 4}}$