find n(A union B) if n(A intersection B')=12 ,n(B intersection A')=13 and n(A intersection B)=5
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10
Answer:
n(a+b) n(a×b)= 12 ,n(b×a)= 13, n(a ×b)
= n²(a²+b²) = 12 and n²(a²+b²)
Step-by-step explanation:
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Answered by
9
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)=7
n(B)=9
n(A∪B)=14
Substituting in 1
14=7+9−n(A∩B)
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