Find “ n “ if ( 2/3 )^3 X ( 2/3 )^ˉ6 = ( 2/3 )2n^ˉ7
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(2/3)³ × (2/3)^-6 = (2/3)^²n - 7.
=> 3 × (-6) = 2n - 7.
=> -18 = 2n - 7.
=> 2n = -18 + 7.
=> 2n = -11.
=> n = -11/2.
=> n = -5.5.
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