Question

find n ,if (3/4)³×(3/4)^-6=(3/4)^2n+1​

Answer 1

Answer:

(3/4)³×(3/4)^-6=(3/4)^2n+1

(3/4)^3-6 = (3/4)^2n+1

(3/4)^-3 = (3/4)^2n+1

-3 = 2n +1

-3-1 = 2n

-4/2 = n.

n = -2.

Answer 2

Answer:

Hope it helps you!!!!!!