Question

find n if 5^{2n+1} ÷ 25 = 5^{5}

Answer 1

hope it helps you to

Answer 2

$\frac{5 {}^{2n + 1} }{25} = {5}^{5} \\ \\ \frac{5 {}^{2n + 1} }{ {5}^{2} } = {5}^{5} \\ \\ {5}^{2n + 1} = {5}^{2} \times {5}^{5} \\ \\ \frac{5 {}^{2n + 1} }{} = {5}^{2 + 5} \\ \\ {5}^{2n + 1} = {5}^{7} \\ \\ { \cancel{5}}^{2n + 1} = \cancel{{5}}^{7} \\ \\ 2n + 1 = 7 \\ \\ 2n = 6 \\ \\ n = \frac{6}{2} \\ \\ \red{ \huge{ \mathtt{n \: = 3}}}$