Question

find n , if (8/3) 2n*(8/3) *(8/3) 5 = (8/3)n *(8/3)2​

Answer 1

From the given sequence 2+3=8, 3+7=27, 4+5=32, 5+8=60, 6+7=72, 7+8=, What number comes next?

First Way:

(2 +3 - 1) × 2 = 08

(3 + 7 - 1) × 3 = 27

(4 + 5 - 1) × 4 = 32

(5 + 8 - 1) × 5 = 60

(6 + 7 - 1) × 6 = 72

(7 + 8 - 1) × 7 = 98

Second Way:

2*(3 + 1) = 08

3*(7 + 2) = 27

4*(5 + 3) = 32

5*(8 + 4) = 60

6*(7 + 5) = 72

7*(8 + 6) = 98

Third Way:

2*1 + 3*2 = 02 + 06 = 08

3*2 + 7*3 = 06 + 21 = 27

4*3 + 5*4 = 12 + 20 = 32

5*4 + 8*5 = 20 + 40 = 60

6*5 + 7*6 = 30 + 42 = 72

7*6 + 8*7 = 42 + 56 = 98

I hope you are understand my solution