find. n if (n+1)!=12(n-1)!
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n+1=12n-12
13=11n
n=13/11= 1²/11 ans
Answered by
1
Answer:
3
I hope it may help u better
Step-by-step explanation:
given, (n+1)!=12(n-1)!
since (n + 1)! = (n+1)(n) (n-1) (n-2).......(3)(2)(1)
so we can write the given thing as
(n+1)(n) (n-1)! = 12(n-1)!
= (n+1)(n) = 12(n-1)!/(n-1)!
= n^2+n=12
n^2-12+n= 0
n^2+n-12=0____1
since the obtained equation is a quadratic equation in terms of n
let's factorise equation,
n^2+n-12=0
= n^2+4n-3n-12=0
=n(n+4) -3(n+4) =0
= (n+4) (n-3) =0
n+4=0 n-3=0
n=-4 n=3
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