Math, asked by fathifarha456, 6 months ago

find. n if (n+1)!=12(n-1)!​

Answers

Answered by Anonymous
0

n+1=12n-12

13=11n

n=13/11= 1²/11 ans

Answered by suchithra17
1

Answer:

3

I hope it may help u better

Step-by-step explanation:

given, (n+1)!=12(n-1)!

since (n + 1)! = (n+1)(n) (n-1) (n-2).......(3)(2)(1)

so we can write the given thing as

(n+1)(n) (n-1)! = 12(n-1)!

= (n+1)(n) = 12(n-1)!/(n-1)!

= n^2+n=12

n^2-12+n= 0

n^2+n-12=0____1

since the obtained equation is a quadratic equation in terms of n

let's factorise equation,

n^2+n-12=0

= n^2+4n-3n-12=0

=n(n+4) -3(n+4) =0

= (n+4) (n-3) =0

n+4=0 n-3=0

n=-4 n=3

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