Question

Find n if (n+1)!=30(n-1)!​

Answer 1

Answer:

(n+1)!=12(n−1)!

(n(n+1)−12)(n−1)!=0 [n!=n(n−1)!]

As (n−1)! cannot be zero

=>(n(n+1)−12)=0

n

2

+n−12=0

n

2

+4n−3n−12=0

(n+4)(n−3)=0

Either n=−4 or n=3

For n=−4,(n−1)! is not defined

=> Value of n is 3

Answer 2

Answer:

n+1=30(n-1)

n+1=30n-30

n-30n= -30-1

-29n=-29

n=-29÷-29

n=1

hence n=1