Math, asked by krishnakrishna36, 1 year ago

Find n if n-1 p3 : np4 = 1:9

Answers

Answered by smartyyash7
2
Hey mate here is your answer :

•n-1P3 / nP4 = 1/9

• 9(n-1) (n-2) (n-3) (n-4) (n-5) (n-6) (n-7) (n-8) = n(n-1) (n-2) (n-3)

• 9(n-4) (n-5) (n-6) (n-7) (n-8) = n

• 9 = n (n-3)

• n²- 3n = 9

• by solving it by quadratic formula we get the value of n is 9

Answered by utuber053
1

Answer:

annswer is 9

Step-by-step explanation:

n-1P3 / nP4 = 1/9

9(n-1) (n-2) (n-3) (n-4) (n-5) (n-6) (n-7) (n-8) = n(n-1) (n-2) (n-3)

9(n-4) (n-5) (n-6) (n-7) (n-8) = n

9 = n (n-3)

n²- 3n = 9

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