Find n if n-1 p3 : np4 = 1:9
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Answered by
2
Hey mate here is your answer :
•n-1P3 / nP4 = 1/9
• 9(n-1) (n-2) (n-3) (n-4) (n-5) (n-6) (n-7) (n-8) = n(n-1) (n-2) (n-3)
• 9(n-4) (n-5) (n-6) (n-7) (n-8) = n
• 9 = n (n-3)
• n²- 3n = 9
• by solving it by quadratic formula we get the value of n is 9
•n-1P3 / nP4 = 1/9
• 9(n-1) (n-2) (n-3) (n-4) (n-5) (n-6) (n-7) (n-8) = n(n-1) (n-2) (n-3)
• 9(n-4) (n-5) (n-6) (n-7) (n-8) = n
• 9 = n (n-3)
• n²- 3n = 9
• by solving it by quadratic formula we get the value of n is 9
Answered by
1
Answer:
annswer is 9
Step-by-step explanation:
n-1P3 / nP4 = 1/9
9(n-1) (n-2) (n-3) (n-4) (n-5) (n-6) (n-7) (n-8) = n(n-1) (n-2) (n-3)
9(n-4) (n-5) (n-6) (n-7) (n-8) = n
9 = n (n-3)
n²- 3n = 9
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