find n if (n+2)!=2550*n!
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(n+2)! = (n+2)(n+1)n!
Thus (n+2)(n+1)n! = 2550*n!
Or, (n+2)(n+1) = 2550
Or, (n+2)(n+1) = 51 * 50
Or, (n+2)(n+1) = (49+2)(49+1)
Thus n = 49
Thus (n+2)(n+1)n! = 2550*n!
Or, (n+2)(n+1) = 2550
Or, (n+2)(n+1) = 51 * 50
Or, (n+2)(n+1) = (49+2)(49+1)
Thus n = 49
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