Question

Find n , if

(n+2)!= 2550 × n!

Answer 1

(n+2)(n+1)n!=2550*n!
(n+2)(n+1)=2550
(n+2)(n+1)=50*51
so
n=49
hope you got ur answer

Answer 2

$\boxed{Question-}$Find n , if

(n+2)!= 2550 × n!

$\huge\bold{Solution}$

We have,

$(n +2)! = 2550 \times n! \\ (n + 2)(n + 1) \times n! = 2550 \times n! \\ (n + 2) \times (n + 1) = 2550 \\ n {}^{2} + 3n - 2548 = 0 \\ (n + 52)(n - 49) = 0 \\ n = 49...............(.n \geqslant 0)$

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