find n if
(n+2)! =60 (n- 1)!
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(n+2)(n+1)(n)(n-1)!=60(n-1)!
(n+2)(n+1)(n)=60
resolves to (n−3)(n2+6n+20)=0
Since it can be shown that (n2+6n+20)=0 has no real solution, n=3
Solution: n=3
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