find 'n' if (n+3)!=110 (n+1)!
Answers
Answered by
34
SEE THIS . THE ANS IS CORRECT. MARK AS BRAINLIEAST
Attachments:
9552688731:
n value not be negative so correct that bro
OKKKK
Answered by
23
(n+3)! = 110 (n+1)!
n+3(n+2)(n+1)! = 110 (n+1)!
(n+3)(n+2) = 110
n²+2n+3n+6 =110
n²+5n+6-110 = 0
n²+5n-104 = 0
n²+13n-8n-104=0
n(n+13)-8(n+13) =0
(n+13) (n-8) =0
n=-13. n=8
so value of n is 8
n+3(n+2)(n+1)! = 110 (n+1)!
(n+3)(n+2) = 110
n²+2n+3n+6 =110
n²+5n+6-110 = 0
n²+5n-104 = 0
n²+13n-8n-104=0
n(n+13)-8(n+13) =0
(n+13) (n-8) =0
n=-13. n=8
so value of n is 8
Similar questions