Find n if n^p^3 = 60.
n^p^3=60 (given
(n-3)
пP3
Answers
Answered by
0
Answer:
Given,
P
5
n
= 20 P
3
n
(n−5)!
n!
= 20
(n−3)!
n!
(n−5)!
n!
= 20
(n−3)(n−4)(n−5)!
n!
1 = 20
(n−3)(n−4)
1
(n−3)(n−4)=20
n
2
−7n+12=20
n
2
−7n+12−20=0
n
2
−7n−8=0
n
2
+n−8n−8=0
n(n+1)−8(n+1)=0
(n−8)(n+1)=0
n=8,−1
Since , n can not be nagative . n
= −1
Hence, n=8.
Answered by
1
Answer:
n=5
Step-by-step explanation:
Given, n^p^3 = 60
So, n^p^3 = 60
or, n!/(n-3)! = 60
or, n(n-1)(n-2)(n-3)!/(n-3)! = 60
or, n(n-1)(n-2) = 60
or, n(n-1)(n-2) = 5×4×3
or, n = 5
As n= 5
So, (n-3) = (5 - 3) = 2
And, n^p^3 = n!/(n-3)!
= 5!/(5-3)! [Putting the value of n = 5]
= 2!×3×4×5/2!
= 3×4×5
= 60
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