find 'n' if the nth term of A.P is 68. for series 5,8,11,14....
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Answered by
4
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Here's your answer...
a = 5
d = 8-5 = 3
T(n) = 68
T(n) = a + (n-1)d
68 = 5 + (n-1)×3
63 = 3n-3
66 = 3n
n = 22
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Here's your answer...
a = 5
d = 8-5 = 3
T(n) = 68
T(n) = a + (n-1)d
68 = 5 + (n-1)×3
63 = 3n-3
66 = 3n
n = 22
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Answered by
5
Hey
a=5. d=8-5=3. Tn68
We know that
Tn=a+(n-1)×d
Put the value of Tn,a. and d
68=5+(n-1)×3
68-5=(n-1)×3
63=(n-1)×3
(n-1)=63/3
(n-1)=21
n=21+1
n=22
a=5. d=8-5=3. Tn68
We know that
Tn=a+(n-1)×d
Put the value of Tn,a. and d
68=5+(n-1)×3
68-5=(n-1)×3
63=(n-1)×3
(n-1)=63/3
(n-1)=21
n=21+1
n=22
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