Question

find n ,n-2,4n-1 and 5n+2 are in AP

Answer 1

Since (n-2), ( 4n-1) and (5n+2) in A.P.

So, 4n-1 - (n- 2) = 5n+2 -(4n-1)

= 4n-1-n+2 = 5n+2-4n+1

= 4n -n -5n + 4n = 2+1-2+1

= 2n = 2

n=1

Answer 2

if given no are in ap then there duff is same
therefore, n-2-n=4n-1-n+2
-2=3n+1
n=-1
therefore no are -1,-3,-5,-7