find n of the sum of n items of ap 48, 45, 42, ....... is 408
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the answer is 121 pls follow me
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Answer:
{ 99 ± √-1191} /6
Step-by-step explanation:
S(n) = n/2 { 2a + (n-1)d }
408 = n/2 { 2×48+ (n-1) (-3) }
916 = n { 96 -3n +3 }
916 = n { 99 -3n }
3n^2 -99n + 916 = 0
n = { 99 ± √ 9801 - 10,992 } / 6
n = { 99 ± √ -1191} /6
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