Math, asked by khwajaahmad646, 1 month ago

Find n so that
4/5^3 ×4/5^-6 =4/5^2n-1..pls guyz solve and send...​

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Answered by meena1974rohit
1

Answer:

(-1/4)-3 × (-1/4)-2 = (4/-1)3 × (4/-1)2 = (-4)3 × (-4)2 = (-4)(3 + 2) = (-4)5 = -45 ... (2/5)-6 = (5/2)6 10. Find the value of n, when 3-7 ×32n + 3 = 311 ÷ 35

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