Question

Find n such that (4/5)⁶×(4/5)⁴= (4/5)^n-2​

Answer 1

Answer:

${\sf{\huge{\bold{\underline{\mathcal{Answer ♡:}}}}}}$

${( \frac{4}{5} )}^{6} \times {( \frac{4}{5} )}^{4} = {( \frac{4}{5}) }^{n - 2} \\ \\ = > {( \frac{4}{5} )}^{6 + 4} = {( \frac{4}{5}) }^{n - 2} \\ \\ = > 6 + 4 = n - 2 \\ \\ = > n - 2 = 10 \\ \\ = > n = 10 + 2 = 12$

${\huge{\boxed{\fcolorbox{red}{black}{ \; \; n \; = \; 12 \; }}}}$