Question

Find n term for an AP. when the first term a = -3 and common difference d = 4.​

Answer 1

Step-by-step explanation:

so we have to find the nth term

TN = a + (n-1)d

TN = -3 + (n-1)4

= 4n - 4 -3

= 4n-7

so the last term would be

4n-7

additional:

so suppose the term is of ten

then we just need to substitute the value of n as 10

Answer 2

Step-by-step explanation:

Here,

the first term = a = (-3)

common difference = d =4

therefore,

$the \: n \: terms \: of \: the \: arithmatic \: progressions \: is$

$a\ \: \frac{}{n} = a + (n - 1)d$

$= ( - 3) + (n - 1)4$

$= 4n - 4 - 3$

$= 4n - 7$

this is the required answer....

hope this will help you....