Question

Find n, where
4ⁿ =2ⁿ⁻¹

Answer 1

Answer:

4^n = 2^n-1

So,

(2^2)^n = 2^n-1

or,

2^2n = 2^n-1

Because, the bases are same, comparing their exponents

we get,

2n = n -1

or,

n = -1

This is the correct answer for the following question.

Hope this helps you ! ｡◕‿◕｡

Answer 2

Answer:

4^n = 2^n-1

2 ^2n = 2^n-1

therefore,

2n = n-1

2n-n+1 =0

n+1=0

n=-1

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