Question

find Nature of Root
B2x2 +2ABX+a^2=0​

Answer 1

Answer: B2 – 4AC < 0

Step-by-step explanation:

Solution:

Given quadratic equation: 2(a2 +b2)x2 + 2 (a+b)x + 1 = 0

If the quadratic equation is of the form AX2 + BX + C = 0 then the discriminant = B2 – 4AC

From the given equation:

A = 2(a2 +b2), B = 2(a+b) and C = 1

Now,

Discriminant of the given equation is given by:

Notice that - 4 is negative number multiplied by a positive number i.e (a - b)2

Hence, discriminant is negative i.e B2 – 4AC < 0

∴ The roots of given quadratic equation are imaginary

Answer 2

Answer:

I have given you the answers

Step-by-step explanation:

please see and. mark me brain list