Math, asked by prernadeora933, 8 months ago

find nature of root in following quadratic equation 2x²+ x minus 1 =0​

Answers

Answered by Uniquedosti00017
1

Answer:

Given quadratic equation is

2x² +x -1 = 0

here,

a = 2

b = 1

c = -1

to find the nature of roots , we find the discriminant,D of the the equation

where,

D = b² -4 ac

so,

D = 1² -4*2*-1

= 1 +8

= 9

clearly , D > 0

so,

the roots are real and unequal..

Step-by-step explanation:

u can calculate the roots by using the formula

x = (-b ± √D)/2a..

.

Answered by abhi52329
0

Answer:

real and unequal

Step-by-step explanation:

2 {x}^{2}  + x - 1 = 0

Let's find the value of the discriminant

 {b}^{2}  - 4ac = 1 - 4 \times 2 \times ( - 1)  \\ = 1 + 8 = 9

Since discriminant is positive and non zero roots are real and unequal

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