Question

Find nature of roots: 2x² - 3x + 5 = 0 *​

Answer 1

Hello,

(i) 2x²–3x+5=0

Comparing Equations with ax²+bx+c=0 ,

(a=2) (b=-3) (c=5)

As we know,

D= b² – 4ac

= (–3)²–4×2×5

= 9 ×40

= –31

Since D<0

Hence, there are no real roots.

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Answer 2

Answer:

roots doesn't exist.

Step-by-step explanation:

D= b^2-4ac

D=(-3)^2 -4(2*5)

D=9-40

D=-31

Discriminant is negative .D<0 . Therefore,roots don't exist.