Question

Find nature of roots of 3x2-2x+1\3 =0

Answer 1

Answer:

Therefore, discriminant b2 – 4ac = (– 2)2 – 4 × 3 ×1/3 = 4 – 4 = 0. Hence, the given quadratic equation has two equal real roots.

Answer 2

Answer:

given eqn is

3x^2-2x+1/3=0

change the above eqn into standard form as shown below

3*3x^2-2*3x+1/(3)=0

9x^2-6x+1=0

here a=9 b=-6 c=1

now find D=b^2-4ac

b^2-4ac

=(-6)^2-4*9*1

36-36

=0

so D=0 there fore roots are real and equal (ans)..