Find nature of roots of quadratic equation √2x^2-3/√2x+1/√2=0
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√2x^2-3/√2x+1/√2=0
=>2x^2-3x+1=0. [Multiplying the whole equation with √2]
Now,a=2,b= -3 and c=1
Discriminant,D = b^2-4ac
=>D=(-3)^2-4(2)(1)
=>D=9-8
=>D= 1
Hence,the roots of above equation are real and distinct in nature
=>2x^2-3x+1=0. [Multiplying the whole equation with √2]
Now,a=2,b= -3 and c=1
Discriminant,D = b^2-4ac
=>D=(-3)^2-4(2)(1)
=>D=9-8
=>D= 1
Hence,the roots of above equation are real and distinct in nature
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