Question

find nature of roots of quadratic equation x² -2√3x - 9 =0 also find the values​

Answer 1

Answer:

The roots are real and distinct

The values are 3√3 and -√3

Step-by-step explanation:

x² - 2√3x - 9 = 0

To find the nature of the roots, we use the Discriminant Formula

D = b²- 4ac

  = (-2√3)²- 4(1)(-9)

  = 12 + 36

  =48

As D>0, the roots are real and distinct

Now, to find the values, We use the quadratic equation

x = -b ± √b²-4ac/2a

  = 2√3 ± √48 / 2(1)

  = 2√3 ± 4√3 / 2

x = 2√3 + 4√3/2 , 2√3 - 4√3/2

  = 3√3, -√3