Question

find nature the roots of the quadratic find equation. if the real roots exit.find then

6x2 + x- 2 =0​

Answer 1

Answer:

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Answer 2

Answer:

the roots are real and distinct and the roots are 1/2;-2/3

Step-by-step explanation:

first of all nature of roots is determined by discriminant which is:

     b^2-4ac   and in the given quadratic a=6,b=1,c=-2

and plugging these we get 1+48=49 which is greater than 0

so the roots are real and distinct(this is nature of roots

and the roots can be found using quadratic formula:

             (-b±√b^2-4ac)/2a which gives us

              (-1±√49)2*6 which gives us the two roots as

  6/12,-8/12=1/2,-2/3  

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