find net force acting on body with differential method
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V = 3t^3 + t - 1/t^2. t=2s. m= 5kg
Taking derivative on both sides wrt t....
d/dt V = d/dt ( 3t^3 + t - 1/t^2 )
Acceleration= 9t^2 + 1 + 2/t^3
Putting value of t....
Acceleration = 9 (4) + 1 + 2/8
= 37 + 1/4 = 37.25 m/s^2
Force = ma
F = 5 × 37.25 = 186.25 Newtons
This is your required Answer.....
Taking derivative on both sides wrt t....
d/dt V = d/dt ( 3t^3 + t - 1/t^2 )
Acceleration= 9t^2 + 1 + 2/t^3
Putting value of t....
Acceleration = 9 (4) + 1 + 2/8
= 37 + 1/4 = 37.25 m/s^2
Force = ma
F = 5 × 37.25 = 186.25 Newtons
This is your required Answer.....
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