Question

find net resistance of the fig

Answer 1

Hi !!

The Resistors are connected in parallel .

Hence ,

R₁ = 2 Ω
R₂ = 5 Ω

1/R = 1/R₁ + 1/R₂
      = 1/2 + 1/5
      = 5/10 + 2/10 = 7/10
1/R = 7/10

7R = 10

R = 10/7
   = 1.42 Ω 

Answer 2

Hey there !!!!

Resistors are in parallel connection

If R₁ and R₂ are connected in a parallel connection

Effective resistance (R)        1/R=1/R₁ + 1/R₂

Here R₁=2Ω  R₂=5Ω

1/R =1/2+1/5 =7/10

R=10/7 = 1.428Ω

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Hope this helped you..................