Question

find no. of atoms in 51g of nitrogen (N = 14 amu)​

Answer 1

Answer:

Mass of 1 mol or (6.022×10

23

molecules) of NH

3

=14+3×1=17 g

Number o f molecules in 34 g NH

3

=

17

34

×6.022×10

23

=12.044×10

23

Number of atoms present in 1 molecule of NH

3

=4

Number of atoms in 34 g NH

3

=4×12.044×10

23

≈48×10

23