Question

find no of atoms of each element in 10g of caco3

Answer 1

Answer:

atomic weight of CaCO3 is 100

Explanation:

atomic weight of CaCO3 is 100 ,

given wt. =10g

no. of moles =given wt.÷atomic wt.

therefore no. of moles =0.1

no. of atoms in 1 CaCO3 molecule = 5

no. of atoms in o.1 mole = 5×o.1×Avagadro’s no.