Find no. of atoms present in 200 gram Calcium carbonate?
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Explanation:
firstly we find the mole of CaCO3 . Now, in CaCO3 1 mol CaCO3 contains 3 mol O . Hence, 36.138*10^23 atoms of oxygen are present in 200 g of caco3.
Answered by
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no of moles= given mass in grams/gam of the element
given mass=200
atomic mass of Caco3= 100
therefore 200/100=2
no of moles =2
no of atoms =2*avagadro no of molecules
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