find no of digits in 4^2013,if log 2=0.3010
Khushleen:
This is a maths question
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Answered by
19
Hey there ! ^_^ .
We know that a has n+1 digits if logx has n digits.
Log4^2013= 2013 log2²= 2(2013)log2
=4026(0.3010)
=1211.826
=1212
So 4^2013 has 1213 digits.
We know that a has n+1 digits if logx has n digits.
Log4^2013= 2013 log2²= 2(2013)log2
=4026(0.3010)
=1211.826
=1212
So 4^2013 has 1213 digits.
Answered by
3
Hope it helps
Thank for asking
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