Find no. of electrons for which n=2, m=0, s=+½.
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Answer:
Answer is 1 electron
Explanation:
N=2 means p shell
L=1 (l of second shell=1)
So p subshell has 3 orbital
Whose value of M=-1,0,1
But we have to take M=0
So total no. Of electron present in m=0 is 2
Now this orbital has Two electron one has s=+1/2 and other has s=-1/2
As per the question only s=+1/2 is required
So total no. Of electron having M=0 and S=+1/2 is only 1
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