find no. of molecules in 56g of methane
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Formula of Methane=CH4
Its mass of One molecule will be: Atomic mass no. of 1 Carbon and Atomic mass no. of 4 Hydrogen.
that is, Mass no.- 12u{mass no. of Carbon}+4(1)u{mass no. of Hydrogen}
that is in total 16 u
Divide it by given amount of methane
then you will get the required no. of molecule,
56g/16u=3.5
required no. of molecule= 3 and a half molecule.
Its mass of One molecule will be: Atomic mass no. of 1 Carbon and Atomic mass no. of 4 Hydrogen.
that is, Mass no.- 12u{mass no. of Carbon}+4(1)u{mass no. of Hydrogen}
that is in total 16 u
Divide it by given amount of methane
then you will get the required no. of molecule,
56g/16u=3.5
required no. of molecule= 3 and a half molecule.
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