Chemistry, asked by miso, 11 months ago

find no of nitrogen atoms present in 65 mg of NaN3

Answers

Answered by Anonymous

10

Answer:

At. Mass of NaNo3=23+14+16*3

=85g =8500mg

Given mass =65mg

No. Of moles =65/8500

=0.00764

1 mole =6.022*10^23

0.00764mole =0.00764*6.022*10^23

miso: thankyou for effort applied but it is NaN3 not NaNO3

snehasingh1212: thank you

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