Question

[Find no. of oxygen atoms in 44.8L of Co2, at S. T. P?]​

Answer 1

Answer:

24.088×10^23 O -atoms

Explanation:

22.4L of CO2 atSTP = 1mole of CO2

= 1mole of O2 molecules

= 2mole of O-atoms

44.8L of CO2 = 4mole of O-atoms

= 4×6.022×10^23

= 24.088×10^23 O-atoms