find no. of proton neutron and electron in 8g of methene
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Atomic mass of C is 12u and of H is 1u
There are 4 H atoms and 1 C atom.
Thus the molecular mass of CH4 is 12+1∗4=16u=16g/mol12+1∗4=16u=16g/mol
Now, 1 C atom contains 6 e−e−
and 1 H contains 1 e−e−
Total no. of electrons in 1 molecule of CH4=6+4=10
No. of moles in 8g CH4 is 8/16=1/2
In one mole CH4 there are 6.023*10^23 molecules
Each molecule contains 10 electrons.
Therefore no. of electrons in in 1/2 moles of CH4=1/2*10*6.023*10^23 electrons
Therefore there are 3.01*10^23electrons in 8g CH4
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