Question

Find no of real roots for equation (x-2)^(x-3)=(x-2)^5

Answer 1

Answer:

put x = 8

then you get

(8-2)^(8-3)=(8-2)^5

(6)^5=(6)^5

7776=7776 answer

you get LHS = RHS

Answer 2

ANSWER

x = 8

only one root

CONCEPT USED

logarithem

EXPLANATION

see attachment

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