find no of ways in which Sixboys
2 girls can be asked to sit in row
that will not sit together?
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Answer:
here is your answer
Explanation:
First make the 7 girls sit on alternate chairs. This arrangement can be done in 7! ways.
Now there are 6 chairs in between the 7 girls. These seven positions can be filled up by 6 boys in 6! ways.
By fundamental counting principle the arrangements can be together made in 7!6! = 5040(720)=3628800 ways
Hence the 6 boys and 7 girls can be made to sit in a row of chairs so that none of the girls sit together in 3628800 ways.
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