Find no of ways to select 10 balls from a large pile of red white and blue balls if the selection has at most 2 red balls
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Answer:
Step-by-step explanation:
My working:
(x+x2+x3+...)3
=x3(1+x+x2+...)3
=x3∑∞r=0(r+3−1r)xr
=∑∞r=0(r+2r)x3+r
Hence the number of ways is (2n−12n−3)=(2n−12).
However, the actual answer is (2n+22)−3(n+12). Did i go wrong somewhere in my proof? Or is it some conceptual understanding gone wrong? Thanks!
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