Question

find normality it is from stiochemistry​

Answer 1

Volume of NaOH solution = 500 ml

Molarity of NaOH solution = 0.2 M

=> milliequivalents of NaOH solution = V * M * n-factor

                                                             = 500 * 0.2 * 1

                                                             = 100 meq

similarly, milliequivalents of KOH solution = 250 * 1 * 1

                                                                      = 250 meq

ATQ

miliequivalents of NaOH + milliequivalents of KOH = Normality of solution * vplume of solution

100 + 250  = N * (500+250)

350/750=N

N=7/15

N=0.46

Answer 2

Answer:

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